# 18.4 Runtime Analysis

Because a left-leaning red-black tree has a 1-1 correspondence with a 2-3 tree and will always remain within 2x the height of its 2-3 tree, the runtimes of the operations will take $$log(N)$$time.

{% embed url="<https://www.youtube.com/watch?index=8&list=PL8FaHk7qbOD6aKgTz2W-foDiTeBEaBoS3&v=uNrmQ_EwJLU>" %}

Here's the abstracted code for insertion into a LLRB:

```
private Node put(Node h, Key key, Value val) {
    if (h == null) { return new Node(key, val, RED); }

    int cmp = key.compareTo(h.key);
    if (cmp < 0)      { h.left  = put(h.left,  key, val); }
    else if (cmp > 0) { h.right = put(h.right, key, val); }
    else              { h.val   = val;                    }

    if (isRed(h.right) && !isRed(h.left))      { h = rotateLeft(h);  }
    if (isRed(h.left)  &&  isRed(h.left.left)) { h = rotateRight(h); }
    if (isRed(h.left)  &&  isRed(h.right))     { flipColors(h);      } 

    return h;
}
```


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